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Difference between revisions of "Store:ACvericale"
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Coordinate: (59.0, -92.3) Calcolo della distanza 'd'rispetto a 1L: <math> | Coordinate: (59.0, -92.3) Calcolo della distanza 'd'rispetto a 1L: <math> | ||
d= \sqrt{(59.0 - 58.3)^2 + (-92.3 + 50.9)^2} = | d= \sqrt{(59.0 - 58.3)^2 + (-92.3 + 50.9)^2}=\sqrt{0.49 + 1714.56} \approx \sqrt{1715.05} \approx 41.42 \, \text{pixel} | ||
</math> Distanza in millimetri: <math> | </math> | ||
Distanza in millimetri: <math> | |||
41.42 \, \text{pixel} \times 0.1 \, \text{mm/pixel} = 4.14 \, \text{mm} | 41.42 \, \text{pixel} \times 0.1 \, \text{mm/pixel} = 4.14 \, \text{mm} | ||
</math> | </math> | ||
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<math> | <math> | ||
d= \sqrt{(46.3 - 58.3)^2 + (-169.5 + 50.9)^2} = | d= \sqrt{(46.3 - 58.3)^2 + (-169.5 + 50.9)^2}=\sqrt{144.0 + 14065.96} \approx \sqrt{14209.96} \approx 119.2 \, \text{pixel} | ||
</math> | </math> | ||
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Coordinate: (44.1, -207.7) Calcolo della distanza rispetto a 1L: <math> | Coordinate: (44.1, -207.7) Calcolo della distanza rispetto a 1L: <math> | ||
d = \sqrt{(44.1 - 58.3)^2 + (-207.7 + 50.9)^2} = | d = \sqrt{(44.1 - 58.3)^2 + (-207.7 + 50.9)^2}=\sqrt{201.64 + 24596.84} \approx \sqrt{24798.48} \approx 157.5 \, \text{pixel} | ||
</math>Distanza in millimetri: <math> | </math> | ||
Distanza in millimetri: <math> | |||
157.5 \, \text{pixel} \times 0.1 \, \text{mm/pixel} = 15.75 \, \text{mm} | 157.5 \, \text{pixel} \times 0.1 \, \text{mm/pixel} = 15.75 \, \text{mm} | ||
</math> | </math> | ||
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<math> | <math> | ||
d= \sqrt{(38.4 - 58.3)^2 + (-136.2 + 50.9)^2} = | d= \sqrt{(38.4 - 58.3)^2 + (-136.2 + 50.9)^2} = \sqrt{396.01 + 7276.09} \approx \sqrt{7672.1} \approx 87.6 \, \text{pixel} | ||
</math> | </math> | ||
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<math> | <math> | ||
d = \sqrt{(36.4 - 58.3)^2 + (-48.2 + 50.9)^2} = | d = \sqrt{(36.4 - 58.3)^2 + (-48.2 + 50.9)^2}=\sqrt{479.61 + 7.29} \approx \sqrt{486.9} \approx 22.1 \, \text{pixel} | ||
</math> | </math> | ||
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<math> | <math> | ||
d = \sqrt{(44.0 - 58.3)^2 + (-34.9 + 50.9)^2} = | d = \sqrt{(44.0 - 58.3)^2 + (-34.9 + 50.9)^2} =\sqrt{204.49 + 256.0} \approx \sqrt{460.49} \approx 21.5 \, \text{pixel} | ||
</math> | </math> | ||
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<math> | <math> | ||
d= \sqrt{(52.9 - 58.3)^2 + (-48.0 + 50.9)^2} = | d= \sqrt{(52.9 - 58.3)^2 + (-48.0 + 50.9)^2} =\sqrt{29.16 + 8.41} \approx \sqrt{37.57} \approx 6.13 \, \text{pixel} | ||
</math> | </math> | ||